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3 years ago

Solve the system of equations.

Mathematics

2 answers:

Dovator [93]3 years ago

7 0

Answer:

option C

Step-by-step explanation:

x = 3y + 1 equation(i)

2x + 4y =12 equation(ii)

First working for equation (ii)

substituting the value of x in equation (ii)

2(3y + 1) + 4y = 12

6y + 2 + 4y = 12

10y = 12 - 2

y = 10/10

y =1

now substitute the value of y in equation (i)

x = 3*1 = 1

x=3 + 1

x = 4

therefore , answer is (4,1)

timurjin [86]3 years ago

6 0

Step-by-step explanation:

C. (4,1)

When x=4 and y=1, the equations become,

4 = 3*1 +1

4=4

2*4+4*1 = 8+4 = 12

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Step-by-step explanation:

Let $\dfrac{a}{b}$ be the original fraction.

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. Hence,

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If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

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Add these two equalities:

$\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36$

Substitute it into the first equation:

$\dfrac{a+6}{6a-36}=\dfrac{a}{6a-36}+1\\ \\\dfrac{a+6}{6(a-6)}=\dfrac{a}{6(a-6)}+1\\ \\a+6=a+6(a-6)\\ \\a+6=a+6a-36\\ \\6a=6+36\\ \\6a=42\\ \\a=7\\ \\b=6\cdot 7-36=42-36=6$