. Does the model represent asexual or sexual reproduction?
1 answer:
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Answer:
Percentage of scores that fall between 70 and 80 = 24.34%
Step-by-step explanation:
We are given a test with a population mean of 75 and standard deviation equal to 16.
Let X = Percentage of scores
Since, X ~ N()
The z probability is given by;
Z = ~ N(0,1) where,
= 75 and
= 16
So, P(70 < X < 80) = P(X < 80) - P(X <= 70)
P(X < 80) = P( <
) = P(Z < 0.31) = 0.62172
P(X <= 70) = P( <
) = P(Z < -0.31) = 1 - P(Z <= 0.31)
= 1 - 0.62172 = 0.37828
Therefore, P(70 < X < 80) = 0.62172 - 0.37828 = 0.24344 or 24.34%
Answer:
See picture attached below
Step-by-step explanation:
We can easily find the answer to your question, if we plot the equation with a graphing calculator or any plotting tool.
The equation is
y = 3 cos (θ + 20) - 4
See attached picture below
phase_shift = 20
max_amplitude = -1
min_amplitude = -7
Period = 2π
