Answer:
Yeah it's ok I think. Also, I can't see the answer you gave so maybe updating the question would be nice.
Answer:
a) final angular speed w2 = 414rpm
b) time to stop t = 312.5s
c) angular distance from start to stop s = s = 1171.88 rev
Explanation:
Average angular speed wa = (w1+w2)/2 = Angular distance/time = s/t
Given;
w1 = 450 rpm = 450/60 rev/s = 7.5 rev/s
s = 180 rev
t = 25s
a)
s/t = (w1+w2)/2
w2 = 2s/t - w1
Substituting the values;
w2 = 2×180/25 - 7.5 = 6.9 rev/s
w2 = 6.9×60rpm = 414rpm
b)
Angular deceleration a = (w1-w2)/t = (7.5-6.9)/25
a = 0.024 rev/s^2
time t for w2 = 0
t = (w1-w2)/a = (7.5-0)/0.024
t = 312.5 s
c)
Angular distance from start to stop s;
s = w1t - 0.5at^2
s = 7.5×312.5s - 0.5×0.024×312.5^2
s = 1171.88 rev
Answer:
t should be 3.57 second
Explanation:
Formula used is v = u+at
In which v is final velocity, u is initial velocity, a is acceleration and t is time.
Substitute each of the info given into the formula and calculate.
49 = 24 + (7)t
t = 3.57s
I believe it is the 2nd one because the ground purifies it over a period of a little while.
Answer:
c.) the sun
Explanation:
the sun provides heat energy