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jeyben [28]
3 years ago
13

A cat is running at 24 m/s. It then accelerates at 7 m/s2. How long will it take the cat to reach a speed of 49 m/s?

Physics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

t should be 3.57 second

Explanation:

Formula used is v = u+at

In which v is final velocity, u is initial velocity, a is acceleration and t is time.

Substitute each of the info given into the formula and calculate.

49 = 24 + (7)t

t = 3.57s

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You throw a 20-n rock vertically into the air from ground level. you observe that when it is a height 15.4 m above the ground, i
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I believe there are two things which we asked to find here:

1. its speed just as it left the ground

2. find its maximum height

 

Solutions:

1. We use the formula:

ΔKE = - ΔPE

where KE is kinetic energy = ½ mv^2, and PE is potential energy = m g h, Δ = change

Therefore:

½ m (v2^2 – v1^2) = m g (h1 – h2)

at initial point, point 1: h1 = 0, v1 = ?

at final point, point 2: h2 = 15.4 m, v2 = 24.2 m/s

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So the rock was travelling at 29.8 m/s as it left the ground.

 

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Rewriting in terms of hmax:

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Therefore the rock reached a maximum height of 45.3 meters.

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