What is (6,2) rotation 270
1 answer:
Given:
The point is (6,2).
To find:
The image of given point after rotation of 270 degrees.
Solution:
Let the given point be P(6,2).
Rotation of 270 degrees means the figure is rotated 270 degrees counterclockwise about the origin. So, the rule of rotation is
Using this rule, we get
Therefore, the image of given point is (2,-6).
You might be interested in
Let O be the intersection of the vertical line through ZX, and the horizontal line through YW.
The coordinates of this point are clearly (5, 2) as it is at the same x-coordinate as X and Z, and y-coordinate as Y and W.
So, YZO is a right triangle. By the Pythagorean theorem:
.
Since all sides of a rhombus are equal, then the perimeter is :
units.
Answer: third choice.
The coordinates of this point are clearly (5, 2) as it is at the same x-coordinate as X and Z, and y-coordinate as Y and W.
So, YZO is a right triangle. By the Pythagorean theorem:
Since all sides of a rhombus are equal, then the perimeter is :
Answer: third choice.
Answer:
2) (-∞, 17]
Step-by-step explanation:
The leading coefficient of the function is negative, so the parabola opens downward. The vertex will be a maximum, the upper end of the range. The lower end of the range will be -∞.
The vertex of the function lies on the axis of symmetry. The maximum can be found by evaluating the function at x=-4.
y = -(-4)² -8(-4) +1 = -16 +32 +1 = 17
The range of the function is (-∞, 17].
