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stellarik [79]
3 years ago
10

iddle" class="latex-formula">
Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

\mathrm{Domain\:of\:}\:\sqrt{2-2\sin \left(x\right)}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:\mathrm{True\:for\:all}\:x\in \mathbb{R}\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:\sqrt{2-2\sin \left(x\right)}:\quad \mathrm{X\:Intercepts}:\:\left(\frac{\pi }{2}+2\pi n,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:\sqrt{2}\right)

\mathrm{Asymptotes\:of}\:\sqrt{2-2\sin \left(x\right)}:\quad \mathrm{None}

\mathrm{Extreme\:Points\:of}\:\sqrt{2-2\sin \left(x\right)}:\quad \mathrm{Maximum}\left(\frac{3\pi }{2}+2\pi n,\:\sqrt{2-2\sin \left(\frac{3\pi }{2}+2\pi n\right)}\right)

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Katie has been withdrawing the same amount of money from her savings account every month. The table below shows the amount of mo
pochemuha
<h3>Answer:  Choice B)  $790</h3>

==============================================================

Explanation:

x = number of months

y = account balance

The first column of the table has (x,y) = (8,470) to mean that on month 8, her balance was $470

Then we have (10, 390) meaning x = 10 and y = 39. As x increased by 2, y dropped by 470-390 = 80 dollars. She withdrew $80 over the course of two months. Therefore, she is withdrawing 80/2 = 40 dollars a month. This is the slope value. It represents the rate of change. We could use the slope formula to find the same result.

Let m = -40 be the slope. It's negative to indicate the value of y goes down as x goes up, or vice versa.

With m = -40, x = 8 and y = 470, we can find the y intercept b like so

y = mx+b

470 = -40*8+b

470 = -320+b

470+320 = b

790 = b

b = 790 is the y intercept, and it represents the initial account balance before Katie started withdrawing money.

In other words, it represents the starting amount of money she has.

-------------------------

As a slight alternative, we could use the point slope form to find the y intercept

y - y1 = m(x - x1)

y - 470 = -40(x - 8)

y = -40(x-8) + 470

y = -40x + 320 + 470

y = -40x + 790

You don't have to use (x,y) = (8,470). You can use any column you want from the table of values. The value of m will be m = -40 the whole time however.

-------------------------

As a way to check to see if we have the correct equation, try plugging in various values of x to see if you get the proper y values as outputs as shown in the table.

For instance, if we tried x = 10, then,

y = -40x + 790

y = -40*10 + 790

y = -400+790

y = 390

That confirms column 2. I'll let you verify the other columns.

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