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2 years ago

Giving 97 points for answer. Need asap for a, b, and c pls help.

Mathematics

2 answers:

Kay [80]2 years ago

4 0

Answer:

sabi 97 tas 49 lang amp ginagawa mo

SIZIF [17.4K]2 years ago

3 0

Answer:

2. being vertically opposite angle.

3.being alternate angle

4.because these points never meet . and they are cut by a transversal line

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A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

If f(x) = 4x ^ 2 and g(x) = x + 1 , find (fg)(x) ).

Irina-Kira [14]

Answer:

$\boxed{\sf \ C \ is \ the \ correct \ answer \ ! \ }$

Step-by-step explanation:

fog(x)=f(g(x))

so it comes

$f(g(x))=f(x+1)=4(x+1)^2$

so C is the correct answer

7 0

3 years ago

Read 2 more answers

Write a word problem whose solutions is |20| =20

Anton [14]

You have 20 candies together in abag 10 red 10 green tou mix them yp togethr in a bag how many candies do you have in the bag

5 0

3 years ago

A local food truck specializes in gourmet grilled cheese sandwiches. Each month, the owners of the truck have a constant total o

Citrus2011 [14]

B would be best answer. 5400s is rent

2.25s amount of sandwich cost and 9.00s selling prices. They all need s and has to be less then!

7 0

2 years ago

Find the sample space for the experiment.

Bingel [31]

Answer:

The sample space is:

$AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE$

Step-by-step explanation:

The sample space of an experiment is a set of all the possible values that satisfies that experiment.

The five supervisors are A, B, C, D and E.

Two are to selected.

The number of ways to select 2 supervisors from 5 is: ${5\choose 2}=\frac{5!}{2!(5-2)!} =\frac{5!}{2!\times 3!} = 10$

The sample space will consist of 10 combinations.

The sample space is:

$AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE$

5 0

3 years ago