Answer:
10 quarters = $2.50
10 nickels = $0.50
that leaves $0.20 for other coins (dimes / pennies)
Step-by-step explanation:
First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.
Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.
This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.
Perimeter = sum of all sides
32 = 2(x+2) + 2(7)
32 = 2x+4 + 14
32 = 2x+18
14 = 2x
/2 /2
7 = x
Answer:
No it is not satisfied
Step-by-step explanation:
The one-way ANOVA is used to measure whether the difference between the means of two independent groups are statistically significant.
For it to be satisfied, there has to be one independent variable which is categorical and one dependent variable. The dependent variable on its own has to be a continuous variable
The assumptions are:
1. Equal variance between population
2. Independence between observations
3. The random samples have to be gotten from a normal population.
It is B because yiu solve
