X=10 let me know if you need the work
Answer:
Step-by-step explanation:
Here you go mate
Use PEMDAS
Parenthesis
Exponent
Multiplication
Division
Addition
Subtraction
Step 1
3(-2x+4) =-6x-12 Equation/Question
Step 2
3(-2x+4) =-6x-12 Remove parenthesis
-6x+12=-6x-12
Step 3
-6x+12=-6x-12 Add 6x to sides
12=-12
Step 4
12=-12 Subtract 12 from sides
-24=0
Answer
No solutions
Hope this helps
Answer:
416.7
Step-by-step explanation:
Answer: 8
The point E in the parallelogram is located at the crossing point of the diagonal line. It can be concluded that the distance of AE is equal to CE, or equal to 1/2 AC. Then you can get three equation like this:
AE=CE
<span>AE=x^2−8
CE=2x .
Using these equation you can find the value of x
AE= CE
</span>x^2−8 = 2x
x^2−2x-8 = 0
(x- 4) (x+2)
x1= 4 x2= -2
Excluding the minus result, you can get that AE= CE= 4
Then AC would be:
AC= AE+CE
AC= 4 + 4= 8
Answer:
<h2>The obtuse angle is 120°.</h2><h2>The acute angle is 60°.</h2>
Step-by-step explanation:
This problem is about two crossing line, when that happens, we have 4 angles, two acute and two obtuse, where adjacent angles are supplementary and vertical angles are equal.
We can form the expression
Where 
is an acute angle and 
is an obtuse angle.}
Using all the given information, we have
Solving for , we have
Therefore, the obtuse angle is 120°, which means the acute angle is 60°, because they are supplementary angles, as we said befor.
