Given data
wavelength λ=2.5 µm =2.5×10⁻⁶m
Diameter d=0.20 mm =0.20×10⁻³m
To find
Angle Θ in radians and degree
Solution
Circular apertures have first dark fringe at
Θ=(1.22λ)/d
Substitute the given values
So
Θ=[1.22(2.5×10⁻⁶m)]/0.20×10⁻³m
Θ=0.01525 rad
or
Θ=0.87°
And that’s why I think it might be C or D.
Answer:
If we have large numbers (b is positive) or small numbers (b is negative), then this way ... 1, and V2i = 100 L, n2i = 5 + 2 + 1 = 8 in vessel 2. ... a good working substance in the barometer.
Answer:
an open system
Explanation:
which is contrasted with the concept of an isolated system which exchanges neither energy, matter, nor information with its environment.