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jeka94
3 years ago
11

If a light ray is traveling from air into a glass prism, how will the direction of the light ray change after it enters the pris

m?
A.
The light ray will be refracted toward the normal.
B.
The light ray will be refracted away from the normal.
C.
The light ray will be refracted perpendicular to the normal.
D.
The light ray will be refracted along the normal.
E.
The light ray will not be refracted.
Physics
1 answer:
vovangra [49]3 years ago
7 0

the light ray will be refracted towards the normal.

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Un ciclista recorre una pista recta de ida y vuelta, en este recorrido:
Elena-2011 [213]

Answer:

a) falso

b) verdadero

c) falso

d) falso

e) verdadero

Explanation:

A) FALSO: la distancia recorrida es independiente del punto de partida y del punto de llegada

B) VERDADERO: para que el ciclista recorra la pista de ida y vuelta es necesario que su velocidad cambie, por lo tanto la aceleración es diferente de cero.

C) FALSO

D) FALSO: en todo momento hay una distancia recorrida en un tiempo en específico, es decir, una rapidez.

E) VERDADERO: el despazamiento sí depende de la distancia entre el punto de llegada y el punto de salida.

6 0
3 years ago
If points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 v battery.
Marizza181 [45]
V = I * R
Where V is the voltage, I is the current and R is the resistance. Using Ohm's law, you require resistance to find the current through the wire. Technically, if the wire has a resistance of 0, you will get infinite current. But this isn't possible. Maybe the negligible resistance refers to the battery's internal resistance - not the wire's resistance. 
7 0
3 years ago
A diver shines a flashlight upward from beneath the water (n = 1.33) at a 32.7° angle to the vertical. At what angle does the li
suter [353]

Answer:

45.93°

Explanation:

The angle of incidence is given as 32.7°

The refractive index of the water that is n_1=1.33

Refractive index of the air that is n_2=1 (because the refractive index of air is 1 )

We have to find the angle at which the light leave the water means angle of refraction

So according to snell's law n_1sini=n_2sinr

1.33sin32.7=1\times sinr

sinr=0.7185

r =45.93°

So the light leave the water at an angle of 45.93°

3 0
4 years ago
3. Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a
34kurt

Answer:

The friction force and the x component for the weight should be the reaction forces that are opposite and equal to the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.  

Explanation:

<u>When the locomotive starts to pull the train up, appears two reaction forces opposed to the action force in the direction of the move. </u>

The first one is due to the friction between the wheels and the ground, it will be the friction force (Fr):

Fr = μ*Pₓ =μmg*sin(φ)        

<em>where μ: friction dynamic coefficient, Pₓ: is the weight component in the x-axis, m: total mass = train's mass + locomotive's mass, g: gravity, and sin(φ): is the angle respect to the x-axis.</em>              

And the second one is the x component for the weight (Wₓ):

Wₓ = mg*cos(φ)  

<em>where cos(φ): is the angle respect to the y-axis.    </em>

<em> </em>

These two forces should be the same as the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.          

3 0
4 years ago
The United States and South Korean soccer teams are playing in the first round of the World Cup. An American kicks the ball, giv
Aleks04 [339]

Answer:v=2.82 m/s

Explanation:

Given

initial velocity of ball(u)=3.6 m/s

ball rolls a distance(s) of 5 m

ball acceleration =-0.5 m/s^2

Velocity of ball when it is intercepted by Korean player

v^2-u^2=2as

v^2=3.6^2+2(-0.5)(5)=7.96

v=\sqrt{7.96}

v=2.82 m/s

3 0
3 years ago
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