Answer:
53 marks
Step-by-step explanation:
To sue a linear equation to solve the given problem, we must assign a function to the score of one of them. Let the score of Azmah be N. Then given that Azmah scored 17 marks more than Yazid, Yazid's score will be
= N - 17
Given that Suzana's score is twice of Yazid's score, then Suzana's score
= 2(N - 17)
If their total score is 161 then
N + N - 17 + 2(N - 17) = 161
4N = 161 + 51
4N = 212
N = 53 . This is Azmah's score
Answer:
Step-by-step explanation:
We have the compound inequality:
Let's solve each of them individually first:
We have:
Divide both sides by 2:
Add 1 to both sides:
We have:
Subtract from both sides:
Divide both sides by -4:
Hence, our solution set is:
Step-by-step explanation:
part A:
ABCD is transformed to obtain figure A′B′C′D′:
1) by reflection over x-axis, obtain the image :
A(-4,-4) B(-2,-2) C(-2, 1) D(-4, -1)
2) by translation T (7 0), obtain the image :
A'(3,-4) B'(5,-2) C'(5, 1) D'(3, -1)
part B:
the two figures are congruent.
the figures that transformed by reflection either or translation will obtain the images with the same shape and size (congruent)
(4,4) are the coordinates of C prime
Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
