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3 years ago

If a tree falls in the middle of the woods and nobody is around to hear it, does it make a sound?

Physics

2 answers:

solong [7]3 years ago

7 0

Yes, everything falling will make a sound unless it is air.

Pavlova-9 [17]3 years ago

6 0

Yes because even if WE couldn't hear it, the tree still makes a sound itself since its hitting the ground with its weight, it makes a dropping noise, animals could still hear it as well, but if nothing is around it, it still makes noise, its just the sound doesn't travel fast/big enough for us to hear it from long distance.

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What is the difference between flashing point, boiling point and melting point

sp2606 [1]

<h3><u>Answer and explanation;</u></h3>

<u>Melting point</u> is defined as the temperature at which solid and liquid phases are in equilibrium. It is the temperature at which a solid changes state from solid to liquid at atmospheric pressure.
<u>Boiling poin</u>t is the temperature at which the vapour pressure of a liquid is equal to the external pressure. It is the temperature at which a substance changes from a liquid into a gas.
<u>The flash point </u>of a flammable liquid or volatile liquid is the lowest temperature at which it can form an ignitable mixture in air. At this temperature the vapor may cease to burn when the source of ignition is removed.

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3 years ago

Read 2 more answers

How many protons are in this atom if it has a balanced charge

Lerok [7]

It would be 20 protons left because 1-19= 20

7 0

2 years ago

A speaker vibrates at a frequency of 200 Hz. What is its period

Daniel [21]

Period, T = 1/ f.
f = frequency = 200 Hz.

Period T = 1/200 = 0.005 seconds.

8 0

3 years ago

A 1.2 g pebble is stuck in a tread of a 0.76 m diameter automobile tire, held in place by static friction that can be at most 3.

Maksim231197 [3]

Answer:

$v=33.764m/s$

Explanation:

Given data

Mass m=1.2 g=0.0012 kg

diameter d=0.76 m

Friction Force F=3.6 N

To find

Velocity v

Solution

From the Centripetal force we know that

$F_{c}=\frac{mv^{2} }{r}$

Where m is mass

v is velocity

r is radius

Substitute the given values to find velocity v

$F_{c}=\frac{mv^{2} }{r}\\v^{2}=\frac{F_{c}(r)}{m}\\ v=\sqrt{\frac{F_{c}(r)}{m}}\\ v=\sqrt{\frac{F_{c}(diameter/2)}{m}}\\v=\sqrt{\frac{(3.6N)(0.76/2)m}{(0.0012kg)}}\\v=33.764m/s$

4 0

3 years ago

Savatey [412]

Answer:

Distance covered is equal to all the distance traveled.

So for example, if you go from A to B, and then from B to C, the total distance covered is AB + BC.

Displacement is equal to the difference between the final position and the initial position.

So if we go from A to B, the displacement is simply the line AB.

While if we go from A to B, and then from B to C, the displacement will be a segment that directly connects A and C, such that:

displacement = √( (AB)^2 + (BC)^2)

Now, if we want to find the points such that the magnitude of the distance covered is equal to the magnitude of the displacement, we need to look at the pairs that are directly connected by a straight line.

Those are:

A to B ( or B to A)

B to C (or C to B)

C to D (or D to C)

7 0

3 years ago