Answer:
[H2] = [I2] = 0.64M; [HI] = 4.72M
Explanation:
Based on the reaction:
H2 + I2 ⇄ 2HI
The K is defined as:
k = 54.3 = [HI]² / [H2] [I2]
<em>Where [] is molar concentration of each reactant at equilibrium</em>
As the initial concentration of HI is 6mol/dm^3 = 6M the equilibrium concentration of each reactant is:
[H2] = X
[I2] = X
[HI] = 6 - 2X
<em>Where X is reaction coordinate</em>
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Replacing:
54.3 = [6-2X]² / [X] [X]
54.3X² = 4X² - 24X + 36
0 = -50.3X² - 24X + 36
Solving for X:
X = -1.12. False solution, produce negative concentrations
X = 0.64M. Right solution
Replacing:
[H2] = 0.64M
[I2] = 0.64M
[HI] = 6 - 2*0.64M = 4.72M
Equilibrium concentrations are:
<h3>[H2] = [I2] = 0.64M; [HI] = 4.72M</h3>
Booooooommmm!.................
Answer:
16.56 g
Explanation:
Mass is the production of Volume and Density.
m = V. d = 6 × 2.76 = 16.56 g
Answer: is the reducing agent
Explanation:
Oxidation reaction : When there is an increase in oxidation state number.
Reduction reaction : when there is a decrease in oxidation state number.
Fe has undergone oxidation, as its oxidation state is changing from+2 to +3.
Mn has undergone reduction, as its oxidation state is changing from +7 to +2.
The chemical agent which itself get oxidized and reduce others is called reducing agent. is a reducing agent.
The chemical agent which itself get reduced and oxidize others is called oxidizing agent. is an oxidizing agent.
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