The molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
<h3>HOW TO CALCULATE MOLAR CONCENTRATION:</h3>
- The molar concentration of a solution can be calculated by dividing the number of moles by its volume.
- According to this question, there are 469 grams of C6H12O6 in 82 milliliters of water.
The number of moles = 469g ÷ 180.156g/mol = 2.6mol
Volume of water in litres = 82/1000 = 0.082L
Concentration of solution = 2.6mol ÷ 0.082L = 31.71M
Therefore, the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
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Answer:
C₁₀H₁₆O
Explanation:
Molecular formula can be determined from parent peak by using rule of thirteen.
Rule of Thirteen:
First divide the parent peak value by 13 as,
= 152 ÷ 13
= 11.69
Now, multiply 13 by 11,
= 13 × 11 (here, 11 specifies number of carbon atoms)
= 143
Now subtract 143 from 152,
= 152 - 143
= 9
Add 9 into 11,
= 9 + 11
= 20 (hydrogen atoms)
So, the rough formula we have is,
C₁₁H₂₀
Now, add one Oxygen atom to above formula and subtract one Carbon and 4 Hydrogen atoms as these numbers are equal to atomic mass of Oxygen atom as,
C₁₁H₂₀ -------O--------> C₁₀H₁₆O
Calculate Hydrogen deficiency index as,
HDI = (2x + 2 - y) / 2
where,
x = C atoms
y = H atoms
HDI = [2(10) + 2 - 16] / 2
HDI = (20 + 2 - 16) / 2
HDI = (22-16) / 2
HDI = 6 / 2
HDI = 3
It means, Camphor contains 1 double bond and two rings. As, HDI of double bond is 1 and HDI of one ring is 1.
We need to separate different components of a mixture to separate the useful components from the non-useful or some harmful components.
Examples:
(a) Tea leaves are separated from tea.
(b) Pebbles are separated form rice and pulse.
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