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Nata [24]
3 years ago
6

How many atoms of Mg are present in 97.22 grams of Mg?

Chemistry
1 answer:
Solnce55 [7]3 years ago
6 0

Answer:

2.439 x 10E24 atoms

Explanation:

from

N=n x NA where

N- number of atoms

n-number of moles and NA is the avogadro's number

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Which reactions have a positive Δrxn? A(g)+B(g)⟶C(g) 2A(g)+2B(g)⟶5C(g) A(s)+B(s)⟶C(g) 2A(g)+2B(g)⟶3C(g)
Sidana [21]

Answer:

A(g)+B(g)⟶C(g) 2A(g)+2B(g)⟶5C(g)

A(s)+B(s)⟶C(g) 2A(g)+2B(g)⟶3C(g):

4 0
3 years ago
a chemist wishes to mix some pure acid with some water to produce 16L of a solution that is 30% acid how much pure acid and how
Aloiza [94]

<u>Answer:</u> The volume of acid and water that must be mixed will be 4.8 L and 11.2 L

<u>Explanation:</u>

We are given:

Volume of mixture = 16 L

Percent of acid present = 30 %

Calculating the percentage of acid present in the mixture:

\Rightarrow 16\times \frac{30}{100}=4.8L

The mixture is made entirely of acid and water.

Volume of acid in the mixture = 4.8 L

Volume of water in the mixture = 16 - 4.8 = 11.2 L

Hence, the volume of acid and water that must be mixed will be 4.8 L and 11.2 L

4 0
3 years ago
How many kilograms of a fertilizer are made of pure P2O5 would be required to supply 1.69 kilogram of phosphorus to the soil?
Alekssandra [29.7K]

Answer:

3.89 kg P2O5 must be used to supply 1.69 kg Phosphorus to the soil.

Explanation:

The molecular mass of P2O5 is

P2 = 2* 31 =           62

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Molecular Mass = 142

Set up a Proportion

142 grams P2O5 supplies 62 grams of phosphorus

x    kg P2O5        supplies 1.69 kg of phosphorus

Though this might be a bit anti intuitive, you don't have to convert the units for this question. The ratio is all that is important.

142/x = 62/1.69            Cross multiply

142 * 1.69 = 62x           combine the left

239.98 = 62x               Divide by 62

239.98/62 = x

3.89 kg of P2O5 must be used.

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3 years ago
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Ivenika [448]

Answer:

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Explanation:

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5 0
2 years ago
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