Answer: 61,750 miles
Step-by-step explanation:
Given : The p-value of the tires to outlast the warranty = 0.96
The probability that corresponds to 0.96 from a Normal distribution table is 1.75.
Mean : 
Standard deviation : 
The formula for z-score is given by : -
Hence, the tread life of tire should be 61,750 miles if they want 96% of the tires to outlast the warranty.
The median (half-above and half-below) could not have changed, because "corrected value was still lower than any other salary" does not change the position of that observation (still least) in the sorted list of salaries.
24 inches. You could simply multiply by 2. Do you want another solution?
Answer: 3.82
Step-by-step explanation: there is a decimal
-10y^2 + (-3y^2) - 4y^2 - (-6y^2) =
-10y^2 - 3y^2 - 4y^2 + 6y^2 =
-17y^2 + 6y^2 =
- 11y^2
