If there are n people, each person could shake hands with 0 people, 1 person, 2 people,... on up to shaking hands with n − 1
people. Count how many different answers there are to asking the person the question "How many hands did you shake?" How many people are there? If the people are the pigeons, and the possible answers to the question "how many hands did you shake" are the holes, can we conclude anything yet? No? How about now noticing that at least one of the holes "I shook hands with noone" or "I shook hands with everyone" has to be empty... now what?
"Since there are more pigeons than holes there must be a hole with at least two pigeons in the same hole" Now, replace the word "pigeons" and "holes" with the appropriate terms for the context of your specific question, remember we are talking about people and number of handshakes they participated in.
Ok use a calculator and do 11 x 11 x 4 then 7 x 7 x 4 and add the products
Step-by-step explanation:
multiple possibilities.
e.g.
we could use Pythagoras to get QR, and then use the law of sine to get angle P.
or we can use the law of sine to get angle R, and then use the rule that the sum of all angles in a triangle is always 180° to get angle P.
I propose the second option :
the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
with a, b, c being the sides always opposite of their associated angles.
33.8/sin(R) = 57.6/sin(90) = 57.6
sin(R) = 33.8/57.6 = 0.586805555...
R = 35.93064691...°
180 = 90 + 35.93064691... + P
P = 54.06935309...°
Answer:
None
Step-by-step explanation:
Answer:
i dont speak spanish
Step-by-step explanation:
sorry i dont understand you...
