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1 year ago

Can someone solve this question?

Mathematics

1 answer:

iren2701 [21]1 year ago

5 0

It’s 26 bc it’s says it right there

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I barely ask questions but I really need help with #3 and a little with 4. On number four I got 1 1/20 which doesn’t seem right.

uranmaximum [27]

Let r, g and b represent red, green and blue.

r+g+b = 74

r=g-1

b=r+g

Again, r+g+b = 74. Let's substitutte r+g for b: r+g+(r+g) = 74.

Next, let's eliminate r. Use r=g-1. Then g-1 + g + g-1 + g = 74

Combining the g terms, 4g - 2 = 74 => 4g = 76 => g = 19

Recall that r=g-1
and
b=r+g

Find r. If r=g-1, and g=19, then r = 19-1=18

Find b: b = r+g = 18+19=37

So there are 37 blue candies, 18 red candies and 19 green candies.

Check: 37+18+19=74 ??? Yes.

8 0

2 years ago

Antonio finds a pair of skis that cost $350 before tax. Sales tax is 6%. What is the total cost Antonio will have to pay for the

Ksju [112]

Answer:

$371

Step-by-step explanation:

5 0

2 years ago

Kathy's lunch cost $16 which included tax. Kathy tipped 20% and reached for a $20 bill. Did she have enough money? Please show y

e-lub [12.9K]

Yes she does have enough here's my work

16 times .20 equals 3.2 and the add 3.2 to 16 and get $19.20

7 0

2 years ago

(look at the images) can i get help on these?

Svetlanka [38]

Answer:

see explanation

Step-by-step explanation:

JK + KL = JL , substitute values

2x + 1 + 6x = 81, that is

8x + 1 = 81 ( subtract 1 from both sides )

8x = 80 ( divide both sides by 8 )

x = 10

Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21

KL = 6x = 6 × 10 = 60

--------------------------------------------------------------

JK + KL = JL , substitute values

2x + x + 2 = 5x - 10 , that is

3x + 2 = 5x - 10 ( subtract 3x from both sides )

2 = 2x - 10 ( add 10 to both sides )

12 = 2x ( divide both sides by 2 )

6 = x

Thus

JK = 2X = 2 × 6 = 12

KL = x + 2 = 6 + 2 = 8

JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20

------------------------------------------------------------

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)

d = $\sqrt{(1-7)^2+(-5-3)^2}$

= $\sqrt{(-6)^2+(-8)^2}$

= $\sqrt{36+64}$

= $\sqrt{100}$ = 10

3 0

2 years ago

A circle that has a center at the point (3, -2) with a radius of 6. Write an equation for the circle.

crimeas [40]

Answer:

(x – 3)^2+ (y +2)^2 = 36

Step-by-step explanation:

Given data

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r^2,

where (h, k) represents the coordinates of the center of the circle

h=3

k=-2

r= 6

Substitute

(x – 3)^2+ (y – (-2))^2 = 6^2

(x – 3)^2+ (y +2)^2 = 36

Hence the expression for the equation of the circle is

(x – 3)^2+ (y +2)^2 = 36

5 0

2 years ago

Can someone solve this question?​

Can someone solve this question?