So all you need to do if find the min of the function:
f(x)=0.04x^3-4x^2-176x
f'(x)=0.12x^2-8x-176
The only zero for this is x=84.105 <---first
Plug this into f(x) to get f(84.105)=-19300 <---second
The answer is 17/5. First you multiply 5*3=15 then you add 2 which your answer is 17/5.
Answer:
1. 2/25
2. 4/15
Step-by-step explanation:
1. P(Y∩X)
Since P(X) =2/3 , P(Y) =2/5 , and P(X|Y) =1/5, this is a conditional probability.
So P(Y∩X) = P(Y)P(X|Y) = 2/5 × 1/5 = 2/25
2. P(Y)· P(X)
P(Y)· P(X) = 2/3 × 2/5 = 4/15
