Multiply both sides by 2 and then add them together to get the perimeter (2L + 2W).
To get the area multiply the two sides by eachother (L x W) Brainly please so others can see if possible.
Answer:
Step-by-step explanation:
Answer:
Each share lost $20 in value over 4 days time
Step-by-step explanation:
$5 loss for 4 days
5 x 4 = 20
$20 loss in 4 days.
This looks like an odd problem.
Just start with a simple expression with 7 as a factor, and then multiply it out.
For example:
7(x+1)(x+2)
Here 7 could be the GCF.
Now multiply it out:
7(x^2+3x+2) =
7x^2+21x+14
So our factorable polynomial is 7x^2+21x+14
And its two equivalent forms are:
7(x^2+3x+2)and7(x+1)(x+2)
Answer:
Practical domain: ![v\in[0,230]\ or\ 0\leqslant v\leqslant 230](https://tex.z-dn.net/?f=v%5Cin%5B0%2C230%5D%5C%20or%5C%200%5Cleqslant%20v%5Cleqslant%20230)
Roger can earn $510 at most.
Step-by-step explanation:
We are given the function
![E(v)=50+2v](https://tex.z-dn.net/?f=E%28v%29%3D50%2B2v)
Which gives the earnings of Roger when he sells v videos. Since the play’s audience consists of 230 people and each one buys no more than one video, v can take values from 0 to 230, i.e.
![v\in[0,230]\ or\ 0\leqslant v\leqslant 230](https://tex.z-dn.net/?f=v%5Cin%5B0%2C230%5D%5C%20or%5C%200%5Cleqslant%20v%5Cleqslant%20230)
That is the practical domain of E(v)
If Roger is in bad luck and nobody is willing to purchase a video, v=0
If Roger is in a perfectly lucky night and every person from the audience wants to purchase a video, then v=230. It's the practical upper limit since each person can only purchase 1 video
In the above-mentioned case, where v=230, then
![E(230)=50+2(230)=50+460=510](https://tex.z-dn.net/?f=E%28230%29%3D50%2B2%28230%29%3D50%2B460%3D510)
Roger can earn $510 at most.