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4 years ago

What is the area of a rectangle with width 2/5 inches and length 3/5 inches?

Mathematics

2 answers:

gladu [14]4 years ago

8 0

Answer:

Step-by-step explanation:

Area of rectangle = length * width

$=\frac{3}{5}*\frac{2}{5}\\\\=\frac{3*2}{5*5}=\frac{6}{25}in^{2}$

butalik [34]4 years ago

8 0

Answer:

B 6/25 in2

Step-by-step explanation:

2/5=0.4

3/5=0.6

0.4 × 0.6= 0.24

0.24=24/100

Simplify

6/25

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Darius is saving money to go to a gaming summer camp. He already has $95 in the bank. His goal is to earn $900 so he can pay for

Gnesinka [82]

Answer:

23 weeks

Step-by-step explanation:

900 - 95 = 805

He only has to save up $805 now.

How many times does 35 go into 805?

35 x 23 = 805

805 ➗35 = 23

4 0

4 years ago

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays. Assuming the

AysviL [449]

Answer:

1.83% probability there are no car accidents on that stretch on Monday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays.

This means that $\mu = 4$

What is the probability there are no car accidents on that stretch on Monday?

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4}*(4)^{0}}{(0)!} = 0.0183$

1.83% probability there are no car accidents on that stretch on Monday

5 0

3 years ago

in a certain population, 11% of people are left-handed. Suppose that you plan to randomly select 100 people and ask each person

Assoli18 [71]

Answer:

c. A and C

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=100, p=0.11)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=100*0.11=11 > 10 \geq 10$

$n(1-p)=100*(1-0.11)=99 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=100*0.11=11$

$\sigma=\sqrt{np(1-p)}=\sqrt{100*0.11(1-0.11)}=3.129$

Part A

We want this probability:

$P(X \geq 12) = 1-P(X$

The z score is defined as

$Z=\frac{x-\mu}{\sigma}$ .

$P(X \geq 12) = 1-P(X$

Part B

P(X>12) = 1-P(X\leq 12) = 1-P(Z< \frac{12-11}{3.129})=1-0.625=0.375[/tex]

Part C

$P(10\leq X \leq 14) = P(X$

The z score is defined as

$Z=\frac{x-\mu}{\sigma}$ .

$P(10 \leq X \leq 14) =P(Z< \frac{14-11}{3.129}) -P(Z< \frac{10-11}{3.129})=P(Z$

So then the best option is : c. A and C

8 0

4 years ago

7/4x^2 -2 = - 0.05x + 4

nata0808 [166]

Answer:

$x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}$

Step-by-step explanation:

Step One: Convert

49/16x^2-2=-0.05x+4

Step Two: Multiply Both Sides by 80

245x^2-160=-4x+320

Step Three: Move everything to the left

245x^2+4x-480=0

Final Step: Quadratic Formula

$x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}$

6 0

4 years ago

A club began with 3 members. Each month, each member brought one new member. Which function can be used to determine the number

skad [1K]

<h3>The needed function which represents the club members after x months is : $C(x) = 3+ (3)^x$ </h3>

Step-by-step explanation:

The initial members in the club = 3

⇒ a = 3

Also, let us assume the needed function is denoted by C(x).

Now, each member brings one new member in the club in 1 month.

So, the number of members in club after 1 month

= Initial members + Addition of members

= 3 + 3 = 6

or , $C(1) = 3 + (3)^1$

Now, at the starting of second month, initial members = 6

Each member brings 1 new member.

So, the number of new members at the end of second month = 6

Total members at the end of second month = 6+ 6 = 12

$\implies C(2) = 12 = 3 + (3)^2$

Continuing the same way, we can see that:

The number of members in club after x months is:

$C(x) = 3+ (3)^x$

Hence, the needed function is : $C(x) = 3+ (3)^x$

8 0

3 years ago