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3 years ago

Please find the fully simplified intercept form!!!! Will mark Brianliest !!!!!!!!!!!

Mathematics

1 answer:

photoshop1234 [79]3 years ago

7 0

Answer:

y = -1/3x - 8

Step-by-step explanation:

Slope intercept form:

y = mx + b

Use two points from the graph:

(0, -8) and (3, -9)

The first point is the y-intercept:

b = -8

Find the slope using the slope formula:

m = (y2 - y1)/(x2 - x1)
m = (-9 - (-8))/3 = -1/3

The equation is:

y = -1/3x - 8

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PLEASE HELP!!!!! 2.) What is the perimeter of a polygon with vertices at (-3, 1), (5, 1), (-3, 4), (5, 4)? 30 points if you can

vredina [299]

Answer:

22 units

Step-by-step explanation:

Known Quantities:

AB = CD and AC = BD

Calculations:

AB = 8
AC = 3
CD = 8
BD = 3

Final Calculations:

perimeter = 2 x (3+8)
perimeter = 22

4 0

2 years ago

Solve 2 log x = log 64. (1 point)

Vladimir79 [104]

Answer:

Step-by-step explanation:

2log(x)=log(64)

By logarithms properties

$xlog_{a}(b)=log_{a}(b^{x} ) \\$

log(x²)=log(64)

When you have log or ln in both sites, you delete them and...

x²=64

$\sqrt[]{x^{2} } =\sqrt{64} \\x=8$

7 0

3 years ago

I need help please it’s difficult

sertanlavr [38]

Subtract the like terms to get your answer of y^2 - 4y - 6

5 0

3 years ago

The error is in the middle: 2(-12) = -24 not 24.

sergiy2304 [10]

Answer:

There is no question so I can not respond with a answer.

Step-by-step explanation:

4 0

3 years ago

Pls help me I will give brainlyiest

storchak [24]

Answer:

57.72 in^2

Step-by-step explanation:

Question 1. Shapes are triangle, semi-circle, and rectangle.

Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.

Question 3.

Rectangle's area:48 in^2

Triangles area:8*4/2= 16 in^2

Circle Area: pi*r^2/2(since its a semi-circle)

3.14*2^2=3.14*4=12.56/2=6.28 in^2

Question 4.

16-6.28=9.72

9.72+48=57.72 in^2

5 0

2 years ago