4x+23=9x-38 21y-1 value of y

Find the length of the highlighted arc. Round your answer to the nearest tenth. *

Firlakuza [10]

Answer:

Approximately 23.6

Step-by-step explanation:

So first find the fraction of the whole circumference the arc is.

270 ÷ 360 = 0.75

The circumference is 10π

0.75 * 10π = 7.5π

7.5π = 23.5619449019 ≈ 23.6

6 0

3 years ago

I need help SOMEONE PLZ HELP ME OUT WITH THIS !! THANK UU

Mama L [17]

Answer:

since they are alternate exteriors, we put a equal sign

2x+78=5x+15

next we subtract 78 on both sides

2x+78-78=5x+15-78

2x=5x-63

then we subtract 5x on both sides

2x-5x=5x-5x-63

-3x=-63

after that we divide -3 on both sides

-3x/-3=-63/-3

and the answer is

x=21

Step-by-step explanation:

8 0

2 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .