5 or more round up
4 or less round down
Answer:
201.06
Step-by-step explanation:
Area of circle: 
r = 1/2d = 1/2(16) = 8
The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
brainly.com/question/4785696
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Answer:
-41.29* 10^-7
Step-by-step explanation:
You would change the order of the numbers by multiplying -4.44 and 9.3 together and multiply 10^-7 and 10^0. Which would now look like this:
(-4.44* 9.3)* (10^-7* 10^0)
-4.44* 9.3= -41.292 and 10^-7* 10^0= 1* 10^-7. So now the equation would look like this:
-41.292* 10^-7
Then round -41.292 to 2 decimal places which would be -41.29.
-41.29* 10^-7
That's the answer. I hope this helps!
9y/5 +5
Im sorry dont have an expression but i hope i got it right
