Given, the density of water is 0.9975 g/ml. Density of water is mass of water per unit volume. Mass of 1 ml of water supposed to be 0.9975 g from density of water. So, mass of 10 ml of water is (0.9975 X 10) g= 9.975 g. From graduated cylinder, mass of 10 ml water is measured to be 9.955 g. So, error for mass of 10 ml water= (9.975-9.955)=0.02 g. Percentage of error for 10 ml water is $\frac{0.02}{10} X 100$ = 0.2. Error in the mass for the 10 ml of water is 0.2 %.

5 0

3 years ago

A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-

Komok [63]

Answer: The cell potential of the cell is +0.118 V

Explanation:

The half reactions for the cell is:

Oxidation half reaction (anode): $Ni(s)\rightarrow Ni^{2+}+2e^-$

Reduction half reaction (cathode): $Ni^{2+}+2e^-\rightarrow Ni(s)$

In this case, the cathode and anode both are same. So, $E^o_{cell}$ will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Ni^{2+}_{diluted}]}{[Ni^{2+}_{concentrated}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = ?

$[Ni^{2+}_{diluted}]$ = $1.00\times 10^{-4}M$

$[Ni^{2+}_{concentrated}]$ = 1.0 M

Putting values in above equation, we get:

$E_{cell}=0-\frac{0.0592}{2}\log \frac{1.00\times 10^{-4}M}{1.0M}$

$E_{cell}=0.118V$

Hence, the cell potential of the cell is +0.118 V

5 0

3 years ago

On left, C l with 2 black dots each above, left, and below and 1 black dot right. On the right, C l with 2 black dots each above

laila [671]

Answer:

Chlorine has seven valence electrons

Explanation:

The dot structure of chlorine was just described in the question. The two dots above, below and by the left are three lone pairs making a total of six electrons. There is another one black dot indicating one electron.

This one electron on both chlorine atoms combine to form the chlorine molecule Cl2.

5 0

3 years ago

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PLEASE HELP ASAP!!!

alexdok [17]

Answer:

Answers are bellow.

Explanation:

The element with electron configuration 1s22s22p63s1 belong I A group in the periodic table and it is sodium because it loses one electron.

We have periodic table in attachments.

Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table, because it has a single electron in its outer shell, which it readily donates, creating a positively charged ion—the Na+ cation. Its only stable isotope is 23Na.

The free metal does not occur in nature, and must be prepared from compounds.

It is soft metal, reactive and with a low melting point.

8 0

3 years ago

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