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Alex
3 years ago
6

When a 10 ml graduated cylinder is filled to the 10 ml mark, the mass of the water was measured to be 9.955 g. if the density of

water is taken to be 0.9975 g/ml, what is the percent error for the 10 ml of water?
Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0

Given, the density of water is  0.9975 g/ml. Density of water is mass of water per unit volume. Mass of 1 ml of water supposed to be  0.9975 g from density of water. So, mass of 10 ml of water is (0.9975 X 10) g= 9.975 g. From graduated cylinder, mass of 10 ml water is measured to be 9.955 g. So, error for mass of 10 ml water= (9.975-9.955)=0.02 g. Percentage of error for 10 ml water is \frac{0.02}{10} X 100 = 0.2. Error in the mass  for the 10 ml of water is 0.2 %.

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Answer:

pH of the final solution = 3.8

Explanation:

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NaF → Na⁺ +    F⁻

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         according to common ion effect dissociation of weak acid decreases.

        Ka = \frac{[H]^{+}[F]^{-}  }{[HF]}

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{Ka of HF = 3.5 x 10⁻⁴} & Concentration of HF = 30 x 4 x 10⁻³ = 0.12 molar

from equation 1

⇒ [H⁺]  = \frac{3.5 X 10^{-4}X 0.12 }{0.3}     [Concentration of F⁻ ≡ Concentration of NaF]

⇒ [H⁺] = 0.00014

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4 years ago
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Answer:

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Explanation:

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Answer:

a) Representation - (in attachment)

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Explanation:

a)

Representation in attachment.

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b)

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