Question 30
2 answers:
Answer : The reaction will produce (B) 1.57 mole of magnesium hydroxide and (D) 3.14 mole of sodium chlorate.
Explanation :
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 moles of react with 2 mole of
So, 2.72 moles of react with
moles of
That means, in the given balanced reaction, is a limiting reagent because it limits the formation of products and
is an excess reagent.
Now we have to calculate the moles of and
by using the moles of limiting reagent.
As, 2 moles of react to give 1 mole of
So, 3.14 moles of react to give
moles of
And,
As, 2 moles of react to give 2 mole of
So, 3.14 moles of react to give 3.14 moles of
Therefore, the reaction will produce (B) 1.57 mole of magnesium hydroxide and (D) 3.14 mole of sodium chlorate.
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Answer:
K I will attempt
Explanation:
a)
b)
1 : 2 : 2 (I don't know if this is what the question wants but it is what I would answer)
c)
Hydrogen because it requires 2 moles of H2 to react with 1 mole of O2
d)
24 moles of water. Look at stoichiometric coefficient. 2:2 means 24 moles you get 24 moles
e)
Oxygen. 2 < 5/2. Remember, 1 mole of O2 requires 2 moles of H2. But 5/2 is still greater than 2
f)
First, let's find out how many moles of water we can get. Since O2 is the limiting reactant, and O2:H2O ratio is 1:2, we will get 4 moles of H2O. Then, we can multiply 4 by Avogadro's number which is to get the number of molecules. We get: 2.41 * 10^24 molecules of water.