5 times that of initial pressure i.e 1625 kpa
Answer:
Young's modulus of this tendon is .
Explanation:
Given that,
Length of the tendon, l = 19 cm
It is stretched by 4.5 mm,
Force, F = 11.3 N
Average diameter, d = 8.2 mm
Radius, r = 4.1 mm
The formula of Young's modulus of this tendon is given by :
So, the Young's modulus of this tendon is . Hence, this is the required solution.
Using kinematics we can find that the take-off distance is 6163 ft
Given parameters
- The initial and final speed of the plane i = 0 and v = 140 mph
To find
The measurement system allows not to have problems when working in different units, in this case we reduce the speed units
v = 140 mile / h (5280 ft / mile) (1h / 3600 s) = 205.34 ft / s
The kinematics allows to find the relationships between the position, the speed and the acceleration of a body, in this case the movement is in one dimension.
v = v₀ + a t
where v and v₀ are the final and initial velocity, respectively, at acceleration and t the time
a =
a =
a = 3.42 ft / s²
Let's use the expression
v² = v₀² + 2 a x
Where v and v₀ are the final and initial velocity, respectively, at acceleration and x the distance traveled
x =
x =
x = 6163.8 ft
Let's reduce to miles
x = 6163.8 ft (1 mile / 5280 ft)
x = 1.17 mile
In conclusion using kinematics we can find that the take-off distance is 6163 ft
Learn more about kinematics here:
Answer:
car is moving away from, so we does not need to move from his position.
Explanation:
given data
initial frequency = 600 Hz
final frequency = 580 Hz
solution
As we know that by the Doppler effect causes we received frequency of any sources
and
when frequency increases that mean you are moving toward the source or that source is moving towards you
and
when frequency decreases it mean you are moving away from source or the source is moving away from you
and here we have given frequency is decreases from 600 Hz to 580 Hz
so car is moving away from, so we does not need to move from his position.
A person who sells <span>moongphali (groundnuts).</span>