Active transport move molecules from low concentrations to high concentrations.
Let us consider body moves a distance S due to the force F.
Hence the work by the body W = FS
If the force is not along the direction of displacement,then the work by a body for travelling a distance S will be -
where
is the component of the force along the direction of displacement.
![Hence\ W= FScos\theta](https://tex.z-dn.net/?f=Hence%5C%20W%3D%20FScos%5Ctheta)
![= F.S](https://tex.z-dn.net/?f=%3D%20F.S)
As per the question the power P is given as -
![P=\frac{W}{\delta t}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7B%5Cdelta%20t%7D)
![=\frac{F.S}{\delta t}](https://tex.z-dn.net/?f=%3D%5Cfrac%7BF.S%7D%7B%5Cdelta%20t%7D)
![= F.\frac{S}{\delta t}](https://tex.z-dn.net/?f=%3D%20F.%5Cfrac%7BS%7D%7B%5Cdelta%20t%7D)
![= \ F.V](https://tex.z-dn.net/?f=%3D%20%5C%20F.V)
Hence alternative definition of power P = F.V
The pressure of the air at the way its blowing
Answer:
about 2.7liters for women and 3.7liters for men
Explanation:
Answer:
W = 100000 J = 100 KJ
Explanation:
Here we will use the most basic and general formula of work, which is as follows:
![W = Fd](https://tex.z-dn.net/?f=W%20%3D%20Fd)
where,
W = Work Done = ?
F = Force Required = 200 N
d = Length of Track = 500 m
Therefore,
![W = (200\ N)(500\ m)\\](https://tex.z-dn.net/?f=W%20%3D%20%28200%5C%20N%29%28500%5C%20m%29%5C%5C)
<u>W = 100000 J = 100 KJ</u>