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MissTica
3 years ago
15

Which pairs of figures are congruent? Which pairs are similar?

Mathematics
1 answer:
Naily [24]3 years ago
7 0

Answer:

sorry if wrong

Step-by-step explanation:

The first with the triangles is similar

the second one with the circles is non

the third one with the squares is non

the forth one with the different shape is both,

hope this helps

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Need help quick new topic need answers please
ikadub [295]

Answer:

circumference=2xpixradius

Ex: for #1, the radius is 6.4, so, to find the circumference you will do this:

2 times 3.14159265359 times 6.4= circumference.

Step-by-step explanation:

I will get reported if I give all the answers so I tried to help by saying how you can find the circumference answers to the questions.

8 0
2 years ago
4. 1 23 (4 x 5) 10 Evaluate
Alecsey [184]
Answer: -1.1

The answer is: Negative 1 point 1 : -1.1
7 0
3 years ago
HELPP!
jekas [21]
8 miles ? If I am correct
7 0
3 years ago
How many 2.5 inch by 6 inch tiles will fit on a back splash that is 2.5 feet tall and 8 feet long?
Maksim231197 [3]
Area of each of the tiles = (2.5 * 6) inches^2
                                       = 15 inches^2
Now we have to get down to the case of the backsplash
1 feet = 12 inches
Then
Length of the back splash = 8 feet
                                           = (8 * 12) inches
                                           = 96 inches
Height of the back splash = 2.5 feet
                                         = (2.5 * 12) inches
                                         = 30 inches
Then
Area of the back splash = ( 30 * 96) inches^2
                                       = 2880 inches^2
So
The number of tiles required to fit in the back splash = 2880/15
                                                                                     = 192
So 192 tiles will be required to fit in the back splash. I hope the procedure is clear enough for you to understand. 
8 0
3 years ago
Read 2 more answers
Let A and B be subsets of a universal set U and suppose n(U)=400, n(A)=135, n(B)=80, and n(A n B)=60. Find the number of element
Alexxandr [17]
Use A' for A complement, etc. and n = intersection ∩.
n(A' n B')
=n(A u B)'   by the de Morgan's law
=nU-n(nA+nB-n(AnB))     n(A u B) = nA + nB - n(AnB)  and nX'=nU-nX
=400-(135+80-60)
=400-155
=245
5 0
3 years ago
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