a(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x^2-x-10
(x+1)(a(x-1)+b(x-2)+(x+1))=(x+1)(9x-10)
a(x-1)+b(x-2)+x+1=9x-10
Now this equation is much simpler!
(a+b)x-a-2b+x+1=9x-10
(a+b)x-a-2b=8x-11
(a+b-8)x-a-2b-11=0
a+b-8=(a+2b-11)/x
I can't solve it 3 variables and 1 equations means infinite answers so yea.
The answer is 2. Here's why:
First if all, anything to the power of 0 is 1.
So n^0=1.
You need to plug in 3 for m, so then 6(3)^-1.
3^-1=1/3.
6 × 1/3= 6/3=2
2×1=2.
Answer:
d = v/53
Step-by-step explanation:
Divide both sides by 53 to make d the subject of the formula
Answer:
94.90
Step-by-step explanation:
