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3 years ago

Answer my math pleaseeeeeeeee

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

8 0

Answer:

Are ni =)

Step-by-step explanation:

OK are no the picture

svet-max [94.6K]3 years ago

8 0

Answer:

<3 = 60

Step-by-step explanation:

This assumes that nothing happens to line x. If angle one has a value, then < 3 will have the same value because the angles are vertically opposite.

Presumably, the five degrees is measured against line x. If line y moves clockwise, it means that <2 is decreasing and giving 5 of its degrees to <1.

Therefore <1 becomes 5 degrees larger.

<1 = 55 + 5

<1 = 60

That means that angle 3 = 60

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What the answer to the question

Katarina [22]

Answer:

the first option

Step-by-step explanation:

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5 0

3 years ago

Add the following rational number =<br> 3/11 and -5/12

tatiyna

Answer:

-19/132

Step-by-step explanation:

To add fractions, find the lowest common multiple of the two denominators and multiply accordingly to make both denominators the same. In this case, the lowest common multiple of 11 and 12 is 132, so we need to multiply the first number by 12 and the second by 11. So we get $\frac{36}{132} + (-\frac{55}{132} )$ = $\frac{36-55}{132}$ = $\frac{-19}{32}$ $-\frac{19}{132}$

4 0

3 years ago

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$

6 0

2 years ago

11×11=4 22×22=16 33×33=?

Kay [80]

This is your answer <span>33 x 33 = 4^3 = 64</span>

7 0

3 years ago

25 PTS PLEASE HELP QUICK

Ray Of Light [21]

Answer is 3
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4 0

3 years ago

Read 2 more answers