If the sum of six consecutive odd integers is 372, what is the smallest of the six integers?

1 answer:

8 0

straightforward way is to write an equation x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) = 372 and to solve it. That unique solution "x" will be your answer. The more reasonable way is to divide 372 by 6, = 62. Then the three consecutive odd numbers in the DESCENDING order from 62 are 61, 59, 57, giving you the answer 57.

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What 1 thruogh 100 added up them divided

Marina CMI [18]

We can use the sum of an aritmetic sequence
the sum from n=1 to n=r when the first term is a1 and the nth term is an is
$S=\frac{n(a_1+a_n)}{2}$
first term is 1
last term is 100
there are 100 terms so n=100

so the sum is $S=\frac{100(1+100)}{2}$
$S=(50)(101)$
S=5050
now you want us to divide by 10
5050/10=505

fun fact, gauss (famous math guy) did this when he was younger, legend has it that he was assigned this as an in class assigment to kill time but gauss found a neat pattern, he noticed that adding the end terms wer giving the same sum, example, 100+1=101, 2+99=101, etc, so he just needed to find al the pairs and add them all up

answer is 505
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Zigmanuir [339]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

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