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3 years ago

When do I compare real-world numbers?

1 answer:

3 0

The first aim of the numerations and numbers in general is to be able to compare things and to know what is bigger and what is smaller.
We compare numbers every day in our daily routine. For example: on the market, we compare the price of the products (the price of the apples for example refers to a real-world number). Or we compare the temperature during the day and during the night, which is also a real-world number.

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Suppose that y varies directly with x, and y=4 when x=20. find y when x=9

Llana [10]

Answer:

y = 1.8

Step-by-step explanation:

y=kx

4=k(20)

k= $\frac{1}{5}$

When x = 9:

$y=\frac{1}{5} x=\frac{1}{5} (9)\\y=(\frac{9}{5}) = 1.8$

6 0

3 years ago

Martin bought a flower vase from a florist. The box in which the vase was packed was shaped like a rectangular prism.

34kurt

Answer:

the answer is C: 1932 sq. cm

Step-by-step explanation:

You want to break down the sections (which is double for each)

there are 6 rectangles but you will only need to calculate for 3

1st rectangle

a = (25) (12)

a = 300 sq. cm

**then multiply by 2 = 600 sq. cm**

2nd rectangle

a = (12) (18)

a = 216 sq. cm

then 216 * 2 = 432 sq. cm

3rd rectangle

a = (25) (18)

a = 450 sq. cm

then 450 * 2 = 900 sq. cm

Total Surface Area

SA = 600 sq. cm + 432 sq. cm + 900 sq. cm

SA = 1932 sq. cm

8 0

3 years ago

Here is a balanced Hanger. Each triangle weighs 2.5 pounds, each circle weighs 3 pounds, and x represents the weight of each squ

zheka24 [161]

Answer:

4x+2.5+2.5+3+3=2x+2.5+3+3+3 AND 4x+5+6=2x+2.5+6

Step-by-step explanation:

4 0

3 years ago

Which is a better estimate for the weight of a tomato? a. 6 tons b. 6 ounces

Lera25 [3.4K]

6 ounces that is a no brainer

3 0

4 years ago

Read 2 more answers

Abby, Deborah, Mei-Ling, Sam, and Roberto work in a firm's public relations office. Their employer must choose two of them to at

sattari [20]

Answer:

a) Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) 0.1

c) 0.4

d) 0.3

Step-by-step explanation:

a) The sample space must contain every possible combination of two names. Since we dont care about the order of the chosen names, we can describe every element of the sample space as a subset of 2 elements of the set {Abby, Deborah, Mei-Ling, Sam, Roberto}. That subset will represent the names of the chosen persons. With this in mind, we conclude that the sample space is

Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) The cardinality of the sample space Ω is 10. Since all choices are equally likely, any choice will have probability $\frac{1}{10} = 0.1$ , because the 10 of them combined must add up 1.

c) We need to find all possible choices that includes Mei-Ling, those will be our favourable cases. The amount of favourable cases must be divided to the total amount of cases (the cardinality of Ω) in order to obtain the probability of Mei-Ling being chosen. Mei-Ling is included on 4 choices (one for each of her partners), this means that she has a probability of $\frac{4}{10} = 0.4$ to being chosen.

d) We have 3 favourable cases ,the choices {Abby, Deborah}, {Abby, Mei-Ling} and {Deborah, Mei-Ling}, which neither of them contain a man. By dividing that number to the total number of cases, we obtain a probability of $\frac{3}{10} = 0.3$ that neither of the two men are chosen

7 0

4 years ago