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Ierofanga [76]
3 years ago
7

What is the product of (-3s+2t(4s-t)

Mathematics
1 answer:
galben [10]3 years ago
5 0
Use the FOLD method<span>
(a+b)(c+d)=ac+ad+bc+bd

</span><span>−12<span>s<span><span>​^2 </span><span>​​</span></span></span>+ 3st + 8ts − 2<span>t<span><span>​^2</span><span>​​

</span></span></span></span>Collect like terms
-12{s}^{2}+(3st+8st)-2{t}^{2}

Simplify
<span>-12{s}^{2}+11st-2{t}^{2}<span>−12<span>s<span><span>​2</span><span>​​</span></span></span>+11st−2<span>t<span>​<span>2

The answer is = -12s^2 + 11st - 2t^2</span></span></span></span></span>
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If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
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Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

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What is the approximate circumference of a circle with a radius of 30 inches? Use π ≈ 3.14.
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Given:
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