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2 years ago

how to do a multiplication grid please someone tell me. I don't know how to show you a picture of the grid either im sorry :(

Mathematics

2 answers:

____ [38]2 years ago

8 0

Answer: It's hard to explain without a grid...

The grid method is a written method used to teach children multiplication. It involves partitioning numbers into tens and units before they are multiplied. In some schools the grid method is referred to as the box method of multiplication because children learn to partition numbers into a grid of boxes.

Step-by-step explanation:

Elis [28]2 years ago

4 0

Answer:

Step-by-step explanation:

1: Next, add the number down the side

2: Now, we do the actual multiplication

3: Now, do the tens times the tens:

4: And finally: the tens row times the ones column:

5: Now we just need to add the numbers together.

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Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas

Vitek1552 [10]

Answer:

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0

2 years ago

a supplier sells 2 1/4 pounds of mulch for every 1 1/3 pounds of gravel. The supplier sells 172 pounds of mulch and gravel combi

astraxan [27]

2 1/4=2 3/12 and 1 1/3= 1 4/12

3 0

3 years ago

A running group has 38 members. Each group member completed half marathon (13.1 miles). The average time to complete is 110 minu

Vikki [24]

Answer:

They took 4,180 minutes total to complete the course.

Step-by-step explanation:

The average time is given by the sum of each individual time of the members divided by the number of members on the group. So if we want to know the total time they took to complete the course we need to take the average and multiply it by the number of people in the group. So we have:

total time = average*number of members = 110*38 = 4180 minutes

They took 4,180 minutes total to complete the course.

8 0

3 years ago

Find the volume of the following solid. The solid between the cylinder f(x,y)equals=e Superscript negative xe−x and the region

PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy$

Now evaluate,

$\int_{0}^{ln(6)}e^{-x}dx$

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

$\int_{-6}^{6}\frac{5}{6}dy = 10$

So,

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10$

7 0

3 years ago

In the library on a university campus, there is a sign in the elevator that indicates a limit of 16 persons. Furthermore, there

Vedmedyk [2.9K]

Answer:

a) 151lb.

b) 6.25 lb

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

In this problem, we have that:

$\mu = 151, \sigma = 25, n = 16$

a) The expected value of the sample mean of the weights is 151 lb.

(b) What is the standard deviation of the sampling distribution of the sample mean weight?

This is $s = \frac{\sigma}{\sqrt{n}} = \frac{25}{\sqrt{16}} = 6.25$

8 0

3 years ago

how to do a multiplication grid please someone tell me. I don't know how to show you a picture of the grid either im sorry :(​

how to do a multiplication grid please someone tell me. I don't know how to show you a picture of the grid either im sorry :(