The answer is D because 4 hours working on problems are 0 hours of reading
Answer: 0.48
Explanation:
P(A/B) = P(AnB)/P(B) where:
P(A/B) = The probability of event A occurring given that B has occurred.
P(AnB) = The probability of both events A and B occurring.
P(B) = the probability that event B occurs.
So let
P(A) = Probability that the residents of a household own 2 cars.
P(B) = Probability that the annual household income is greater than $25,000.
The question tells us that
P(A/B) = 0.8
Note that: P(A) = 0.7, P(B) = 0.6.
Since we want to work out P(AnB), because it gives the probability that residents have an annual household income over $25,000 and own 2 cars.
We would Rearrange our initial equation to make P(AnB) the subject formula becoming;
P(A/B) = P(AnB)/P(B)
P(B)*P(A/B) = P(AnB)
So, inserting our probabilities into this equation gives:
0.6*0.8 = 0.48
You would have to either make them pay another installment.
Answer:
$0
Explanation:
Scott Company must record the warranty expense and liability regarding the products sold during the years that they occur. For example, the following journal entry must be made to record the warranty expense for year 1:
Dr Warranty expense 25,000
Cr Warranty liability 25,000
During year 2, they will record the warranty expense for that year:
Dr Warranty expense 20,000
Cr Warranty liability 20,000
That means that during year 3, the only warranty expense recorded will be the one related to the goods sold during that year.
Answer:
Interest revenue = $7800*8%/360*60
Interest revenue = $104
Date Journal Entry Debit Credit
Cash $7,904
Notes Receivable $7,800
Interest Revenue $104
