Answer:
236 cm²
Step-by-step explanation:
Height of an equilateral triangle (h) = √3 /2 (l)
l = side of the equilateral triangle.
h = √3 /2 (15)
In an equilateral triangle the orthocenter, centroid, circumcenter and incenter are in the same spot
The center of the circle is the centroid and height match with the median. The radius of the circumcircle is equal to two thirds the height.
Formula for the Radius of the circumcircle = 2/3 h
= 2/3 x √3 /2 (15)
= 5 √3 cm (=radius)
Area of the circle = πr^
= 3.14 x( 5 √3 ) ^
=3.14 x(25*3)
=3.14 x 75
=235.5
=236 cm²
The answer to A is the pic below
The symbol they are using is that of a ray so, order matters.
Ray BC is telling you the ray starts at point B like a line segment BUT continues on towards and through point C rather than stopping at it.
Ray CB is telling you just the opposite; the ray starts at point C, continues on towards and through point B.
Then using trygonometric table or a graph we read that:
Period of cosinus function = 2π
So the last answer is
Answer:
<h2>510.4 ft²</h2>
Step-by-step explanation:
We have:
two trapezoids with bases 15ft and 7ft and height 5ft.
four rectangles 5ft × 11ft, 15ft × 11ft, 9.4ft × 11ft and 7ft × 11ft.
The formula of an area of a trapezoid:
b₁, b₂ - bases
h - height
Substitute:
The formula of an area of a rectangle:
l - length
w - width
The dimensions of rectangle l × w
Subtitute:
The surface area of the figure:
[tex]S.A.=2A_t+A_1+A_2+A_3+A_4\\\\S.A.=2(55)+55+165+103.4+77=510.4\ ft^2[/text]
