Any set of numbers (x, y) for which this inequality is true is a solution.
For example, the point (1, -5) is a solution because fitting it into the inequality gives us
<u>- 5 < - 2</u> which is true.
However, the point (3, 5) wouldn't be a solution because it would give us the inequality
<u>5 < 2</u> which is not true.
XZ ≅ EG and YZ ≅ FG is enough to make triangles to be congruent by HL. Option b is correct.
Two triangles ΔXYZ and ΔEFG, are given with Y and F are right angles.
Condition to be determined that proves triangles to be congruent by HL.
<h3>What is HL of triangle?</h3>
HL implies the hypotenuse and leg pair of the right-angle triangle.
Here, two right-angle triangles ΔXYZ and ΔEFG are congruent by HL only if their hypotenuse and one leg are equal, i.e. XZ ≅ EG and YZ ≅ FG respectively.
Thus, XZ ≅ EG and YZ ≅ FG are enough to make triangles congruent by HL.
Learn more about HL here:
brainly.com/question/3914939
#SPJ1
In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two triangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
Answer:
Step-by-step explanation:
since we know that 
in this expansion is 
thus 
Hope that helps!
Following the example given where "square, then subtract 5" refers to squaring the variable x and then subtracting 5 from it.
f(x) = x² - 5
The "rule" we must then express in function notation is "subtract 6, then square". The rule appears to suggest that the number 6 is being subtracted from the variable x. Then the entire expression is squared, resulting in the following function:
f(x) = (x - 6)²
C = 30.7 degrees, A = 76.3 degrees and a = 15.2
