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irina [24]
2 years ago
8

Ann drove to the store 10 km north of her house and then drove to the library, which is 5 km south of the store. She drove a tot

al distance of 15 km. What was Ann's displacement? O A. 15 km south OB. 5 km north C. 5 km south D. 15 km north SUBMIT​
Chemistry
1 answer:
Diano4ka-milaya [45]2 years ago
6 0

Answer:

C = 5km North

Explanation:

d = 10 - 5 = 5km

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13. What is the atomic mass of an atom if its mass is approximately equal to the following? 1 a. that of carbon-12 b. 4.5 times
12345 [234]

The atomic mass of an atom if its mass is approximately equal to carbon-12 will be 12 and in case of 4.5 times carbon-12 will be 54

Atomic mass of an element is the average mass of the atoms of an element which are measured in atomic mass unit. Or we can also say that the atomic mass is actually the weighted mass is a weighted average of all of the isotopes of elements, in which the mass of each element is multiplied by the abundance of that particular isotope.

So the atomic mass of an atom if the mass is approximately equal to carbon-12 then the mass of the element will be equal to 12 as the atomic mass of carbon-12  is 12.

where as the atomic mass of an atom if its mass is approximately equal to 4.5 times as much as carbon-12 will be ⇒ 4.5×12= 54

To know more about atomic mass

brainly.com/question/16887530

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6 0
1 year ago
A hot air balloon is filled with 15 moles helium gas and 5 moles nitrogen gas. What is the volume of the balloon at 1.01 atm and
kvasek [131]

<u>Given:</u>

Moles of He = 15

Moles of N2 = 5

Pressure (P) = 1.01 atm

Temperature (T) = 300 K

<u>To determine:</u>

The volume (V) of the balloon

<u>Explanation:</u>

From the ideal gas law:

PV = nRT

where P = pressure of the gas

V = volume

n = number of moles of the gas

T = temperature

R = gas constant = 0.0821 L-atm/mol-K

In this case we have:-

n(total) = 15 + 5 = 20 moles

P = 1.01 atm and T = 300K

V = nRT/P = 20 moles * 0.0821 L-atm/mol-K * 300 K/1.01 atm = 487.7 L

Ans: Volume of the balloon is around 488 L


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