Answer:
18.76 g of copper II nitrate
Explanation:
Now recall that we must use the formula;
n= CV
Where;
n= number of moles of copper II nitrate solid
C= concentration of copper II nitrate solution
V= volume of copper II nitrate solution
Note that;
n= m/M
Where;
m= mass of solid copper II nitrate
M= molar mass of copper II nitrate
Thus;
m/M= CV
C= 0.05 M
V= 2.00 L
M= 187.56 g/mol
m= the unknown
Substituting values;
m/ 187.56 g/mol = 0.05 M × 2.00 L
m= 0.05 M × 2.00 L × 187.56 g/mol
m= 18.76 g of copper II nitrate
Therefore, 18.76 g of copper II nitrate is required to make 0.05 M solution of copper II nitrate in 2.00 L volume.
A 0.25m solution of NaCl is defined as a solution consisting of 0.25mol NaCl dissolved in 1kg water:
Which choice fits this definition: None does. I suggest that you recheck the data you have submitted - you have a mixture of moles, mass, etc and it is easy to make a mistake.
d) looks promising if it was: 1.0 mol NaCl dissolved in 4kg water.
I have overlooked C) as possible 0.25mol NaCl in 1kg water as being a little too obvious.
Answer:
Explanation:
The <em>dimensional analysis</em> helps you by focusing your attention into the units: you must set up the equation starting with the available units and add the factors with the units such that the cancelation of numerators and denominators ends up with the desired units: grams of aluminium in this case.
In this case, you start with a mass of 2.56 grams per penny, which is 
, whose value is $200.00 and want to end with the grams of
Aluminium needed.
Then, you must use the mole ratios derived from the chemical equation in a way that the units lead from grams of copper to grams of aluminium.
The equation is:
From which, the mole ratio between copper and aluminium is:
You must also use the atomic masses of Cu and Al which are 63.5g/mol and 27g/mol respectively.
The equation is:
You can check that afeter multiplying all the factors, the most units will cancel and the final units will be grams of Al.
The reactants of the reaction of single replacement that produces ZnCl₂ and H₂ is Zn + 2HCl
Explanation
In a single replacement reaction is a chemical reaction whereby an element react with compound and take the place of another element in that compound.
zn displaces H from HCl to form ZnCl₂ and H₂ according to below equation.
Zn +2HCl → ZnCl₂ + H₂
