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Svet_ta [14]
2 years ago
7

A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by?

Chemistry
1 answer:
AURORKA [14]2 years ago
3 0

A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by ventilation.

The two following principles determine the type of ventilation: Considering the impact of the contaminant's vapour density and either positive or negative pressure is applied.

Consider a vertical tank that is filled with methane gas. Methane would leak out if we opened the top hatch since its vapour density is far lower than that of air. A second opening could be built at the bottom to greatly increase the process' efficiency.

A faster atmospheric turnover would follow from air being pulled in via the bottom while the methane was vented out the top. The rate of natural ventilation will increase with the difference in vapour density. Numerous gases that require ventilation are either present in fairly low concentrations or have vapor densities close to one.

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5 0
3 years ago
The number of possible different orbital shapes for the third energy level is
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option c) 3 is the correct option

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3 years ago
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6 0
3 years ago
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How do you do this? very confused
Vlad [161]
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4 0
3 years ago
If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution?
Alborosie

Concentration is the number of moles of solute in a fixed volume of solution

Concentration(c) = number of moles of solute(n) / volume of solution (v)

25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.

original solution molarity - 0.150 M

number of moles of LiOH in 1 L - 0.150 mol

number of LiOH moles in 0.125 L  - 0.150 mol/ L x 0.125 L = 0.01875 mol

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c = 0.01875 mol / 0.150 L  = 0.125 M

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7 0
3 years ago
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