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3 years ago

Explain the 4 methods of separating mixtures

1 answer:

8 0

1) chromatography- separation by inner molecular attractions.

2) distillation- separation by boiling point differences.

3) filtration- separation by particle size

4) crystallization- separation by solubility

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Corn,sugar,algae,and sewage can be used as fuel for engines. these are all examples of

fgiga [73]

I believe its biofuels.

8 0

3 years ago

Read 2 more answers

KNO3(s) --> K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r

nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

$KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)$

Explanation:

Mass of aqueous solution = m = 100 g

Specific heat of solution = c = 4.18 J/gºC

Change in temperature = $\Delta T=T_f-T_i$

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

$Q = mc\Delta T$

$Q=100 g\times 4.18 J/g^oC\times (-8.4^oC)$

Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= $\frac{10.1 g}{101 g/mol}=0.1 mol$

$KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)$

The heat of solution =

$\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol$

So, the equation correctly showing the heat of solution

$KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)$

4 0

4 years ago

What is the molar mass of methanol (CH3OH)?

HACTEHA [7]

Molar mass of methanol=12 + 1×3 + 16 + 1=32g

8 0

3 years ago

Read 2 more answers

I find that there are 500 atoms of U-235 and 1500 atoms of Pb-207. If we assume the mineral contained only parent and no daughte

swat32

Explanation:

From the question it can be infered that initially only parent atoms were present in the rock and no daughter atom. So, initially there was only uranium atom and no lead atom. So, in total there were 500+1500= 2000 uranium atom. And no lead tom was there.

3 0

4 years ago

An ideal gas in a closed container initially has a volume V and Temperature T the final tempera is 5/4T and the final pressure i

Anettt [7]

Answer:

$V_2 = \frac{5V}{8}$

Explanation:

I am assuming you are saying what is the final volume of the gas

Known :

Initial volume (V1) = V

Initial temperature (T1) = T

Final temperature (T2) = 5/4 T

Initial pressure (P1) = P

Final pressure (P2) = 2P

Wanted: Final volume (V2)

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{PV}{T} = \frac{(2P)V_2}{(5/4)T}\\\frac{V}{1} = \frac{(2)V_2}{5/4}\\5/4V = 2V_2\\\\V_2 = \frac{5V}{8}$

5 0

2 years ago