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Harrizon [31]
4 years ago
14

____ is stored in a fossil fuel, and released in the form of kinetic energy when burned. Apex

Chemistry
1 answer:
Damm [24]4 years ago
5 0

Potential Chemical energy

Explanation:

Potential Chemical energy is stored in a fossil fuel and released in the form of kinetic heat energy when it is burnt.

Potential energy is the energy at rest in a body. It is that energy when no change is happening to a body. There are different forms of potential energy. A good example in fossil fuels is chemical energy.

Kinetic energy of a body is the energy due to the motion of a body. It occurs when particles of a medium are agitated. An example of kinetic energy in fossil fuel occurs when it is burnt.

  • the formative process of a fossil fuel stores chemical energy.
  • the process prevents energy rich carbon atoms from being converted back into nature by decomposers.
  • the hydrocarbon chain stores chemical energy
  • the energy is released when the molecules are burnt and they form heat energy, a form of thermal energy.

learn more:

Fossil fuel brainly.com/question/9231468

#learnwithBrainly

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Abbreviation for mole
Sedbober [7]

Answer:

Maybe mol

Explanation:

6 0
3 years ago
WILL GIVE BRAINLIEST!!!
Rus_ich [418]

Answer:

The answer is B

Explanation:

The answer is B because representative particles can only be atoms.

3 0
3 years ago
A container of gas has a volume of 280 mL at a temperature of 22 Celsius if the pressure remains constant what is the volume 44
d1i1m1o1n [39]

Answer:

300.9mL

Explanation:

Given parameters:

V₁  = 280mL

T₁ = 22°C

T₂  = 44°C

Unknown:

V₂ = ?

Solution:

To solve this problem, we apply Charles's law;

  it is mathematically expressed as;

            \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

We need to convert the temperature to kelvin;

       T₁ = 22°C = 22 + 273 = 295K

       T₂  = 44°C = 44 + 273  = 317K

Input the parameters and solve;

        \frac{280}{295}   = \frac{V_{2} }{317}

  V₂ x 295 = 280 x 317

  V₂ = 300.9mL

5 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
4 years ago
Read 2 more answers
What is the pH of a solution with (H+] = 1 x 103 M?
luda_lava [24]
It is 5 hope this helps
5 0
3 years ago
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