All categories

3 years ago

What is the method for oxygen for rusting

Chemistry

2 answers:

Georgia [21]3 years ago

7 0

Answer: Hope this helps

Explanation:

Rust is formed when oxygen comes into sustained

krok68 [10]3 years ago

3 0

The answer is Oxidation

You might be interested in

The picture shows a scientist operating an instrument that measures earthquakes. Identify the TWO terms from the list below that

Liula [17]

Answer:

The answers are A) Seismograph, and B) Primary (P) Waves

Explanation:

A is one because a seismograph measures seismic waves to gauge the intensity of an earthquake, such as B, P Waves, which are the earliest waves, the ones that tell you an earthquake is coming.

Good Luck!

5 0

3 years ago

when switch s is closed positive ions will undergo 1) oxidation at electrode B 2) oxidation at electrode A 3) reduction at elect

stepladder [879]

Answer:

reduction at electrode B

Explanation:

4 0

4 years ago

The human body has several major systems. Most body systems have multiple functions. Which of the following is NOT a major funct

tensa zangetsu [6.8K]

Answer:D

Explanation:

i got it right LOL

8 0

3 years ago

Initially, [NH3(g)] = [O2(g)] = 3.60 M; at equilibrium [N2O4(g)] = 0.60 M. Calculate the equilibrium concentration for NH3.

natima [27]

The question is incomplete, here is the complete question:

Consider the reaction $4NH_3(g)+7O_2(g)\rightarrow 2N_2O_4(g)+6H_2O(g)$

Initially, $[NH_3(g)]=[O_2(g)]$ = 3.60 M; at equilibrium $[N_2O_4(g)]=0.60M$ . Calculate the equilibrium concentration for $NH_3$

<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M

<u>Explanation:</u>

We are given:

Initial concentration of $[NH_3(g)]$ = 3.60 M

Initial concentration of $[O_2(g)]$ = 3.60 M

For the given chemical equation:

$4NH_3(g)+7O_2(g)\rightarrow 2N_2O_4(g)+6H_2O(g)$

Initial: 3.60 3.60

At eqllm: 3.60-4x 3.60-7x 2x 6x

We are given:

Equilibrium concentration of $[N_2O_4(g)]$ = 0.60 M

Evaluating the value of 'x'

$\Rightarrow 2x=0.60\\\\\Rightarrow x=\frac{0.60}{2}=0.2$

So, equilibrium concentration of $NH_3=(3.60-4x)=(3.60-(4\times 0.2))=2.8M$

Hence, the equilibrium concentration of ammonia is 2.8 M

6 0

3 years ago

The temperature of a 500 ml sample of gas increases from 150 k to 300 k. what is the final volume of the sample of gas, if the p

seropon [69]

Upon a constant pressure (P), volume (V) of a gas will vary in direct proportion to changes in temperature (T). So V1/T1 = V2/T2
V2 = V1T2/T1 = (500)(300)/150
V2 = 150000/150 = 1000 mL

5 0

3 years ago