Answer:
A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C
Explanation:
A₃B₈ + C₂ –> AC₂ + B₂C
The equation can be balance as illustrated below:
A₃B₈ + C₂ –> AC₂ + B₂C
There are 3 atoms of A on the left side and 1 atom on the right side. It can be balance by writing 3 before AC₂ as shown below:
A₃B₈ + C₂ –> 3AC₂ + B₂C
There are 8 atoms of B on the left side and 2 atoms on the right side. It can be balance by writing 4 before B₂C as shown below:
A₃B₈ + C₂ –> 3AC₂ + 4B₂C
There are 2 atoms of C on the left side and a total of 10 atoms on the right side. It can be balance by writing 5 before C₂ as shown below:
A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C
Now, the equation is balanced.
