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3 years ago

10

Shukri mengedipkan mata beberapa kali apabila mata nya dimasuki habuk. Apakah jenis

1 answer:

Cerrena [4.2K]3 years ago

3 0

Answer:

No sé bro porque im un pilipino triste bro plss no me reporta .... dios bendiga al hermano

Explanation:

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The tabulated data were collected for this reaction:

erastovalidia [21]

Answer:

ai) Rate law, $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

aii) Rate constant, k = 1.25

b) Overall order of reaction = 1.5

Explanation:

Equation of Reaction:

$CH_{3} Cl (g) + 3 Cl_2 (g) \rightarrow CCl_4 (g) + 3 HCl (g)$

If $A + B \rightarrow C + D$ , the rate of backward reaction is given by:

$Rate = k [A]^{a} [B]^{b}\\k = \frac{Rate}{ [A]^{a} [B]^{b}}\\k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$

k is constant for all the stages

Using the information provided in lines 1 and 2 of the table:

$0.014 / [0.05]^a [0.05]^b = 00.029/ [0.100]^a [0.05]^b\\0.014 / [0.05]^a [0.05]^b = 00.029/ [2*0.05]^a [0.05]^b\\0.014 / = 0.029/ 2^a\\2^a = 2.07\\a = 1$

Using the information provided in lines 3 and 4 of the table and insering the value of a:

$0.041 / [0.100]^a [0.100]^b = 0.115 / [0.200]^a [0.200]^b\\0.041 / [0.100]^a [0.100]^b = 0.115 / [2 * 0.100]^a [2 * 0.100]^b\\$

$0.041 = 0.115 / [2 ]^a [2]^b\\ \[[2 ]^a [2]^b = 0.115/0.041\\ \[[2 ]^a [2]^b = 2.80\\\[[2 ]^1 [2]^b = 2.80\\\[[2]^b = 1.40\\b = \frac{ln 1.4}{ln 2} \\b = 0.5$

The rate law is: $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

The rate constant $k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$ then becomes:

$k = 0.014 / ( [0.050] [0.050]^(0.5) )\\k = 1.25$

b) Overall order of reaction = a + b

Overall order of reaction = 1 + 0.5

Overall order of reaction = 1.5

3 0

3 years ago

The rate constant for a certain reaction is k = 4.50×10−3 s−1 . If the initial reactant concentration was 0.400 M, what will the

SIZIF [17.4K]

<u>Answer:</u> The concentration of reactant after the given time is 0.0205 M

<u>Explanation:</u>

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $4.50\times 10^{-3}s^{-1}$

t = time taken for decay process = 11.0 min = 660 s (Conversion factor: 1 min = 60 s)

$[A_o]$ = initial amount of the reactant = 0.400 M

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$4.50\times 10^{-3}s^{-1}=\frac{2.303}{660s}\log\frac{0.400}{[A]}$

$[A]=0.0205M$

Hence, the concentration of reactant after the given time is 0.0205 M

4 0

3 years ago

A solution was prepared by dissolving 38.0 g of KCl in 225 g of water. Part A Calculate the mass percent of KCl in the solution.

AveGali [126]

The total mass is the sum of mass of KCl and mass of water:

total mass = 38 g + 225 g

total mass = 263 g

Therefore the mass percent of KCl is:

% KCl = (38 g / 263 g) * 100%

<span>% KCl = 14.45%</span>

7 0

3 years ago

Help me please I need to know

rjkz [21]

C- Electron
A-Nucleus
B-Neutron
D-Protron

7 0

3 years ago

What is the mathematical equation used when solving calorimetry problems? What does each variable in the equation represent?

liubo4ka [24]

Answer : The mathematical equation used when solving calorimetry problems is:

$q=m\times c\times \Delta T}$

Explanation :

Calorimetry : It is determining the changes in the energy of a system by measuring the heat transferred with surroundings.

Formula used :

$q=m\times c\times \Delta T}$

where,

c = specific heat capacity of calorimeter

m = mass of a substance

q = heat required

$\Delta T$ = change in temperature of substance

7 0

3 years ago