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3 years ago

What does energy and transfer mean? in your opinion.... please

Physics

2 answers:

prisoha [69]3 years ago

7 0

Answer:

Energy transfer is the process by which energy is relocated from one system to another, for example, through the transfer of heat, work or mass transfer.

IgorLugansk [536]3 years ago

5 0

A pendulum is a simple example of energy transfer – converting potential energy to kinetic energy over and over until the small amount of energy lost to heat and air resistance causes the pendulum to come to rest.

capacity to do work. energy transfer. Noun. The conversion of one form of energy into another, or the movement of energy from one place to another. energy transformation.

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PLEASE HELP QUICKLY 50 POINTS<br> Fracturing can emit ______waves through the ground.

drek231 [11]

Answer:

Fracturing can emit seismic waves through the ground.

Explanation:

I believe the answer is seismic, I've studied this before.

5 0

3 years ago

A horizontal pipe narrows from a radius of 0.250 m to 0.1000 m. If the speed of the water in the pipe is 1.00 m/s in the larger-

umka21 [38]

Answer:

6.25 m/s

196 kg/s

Explanation:

The areas of the pipe from big to small:

$A = \pi R^2 = \pi*0.25^2 = 0.196 m^2$

$a = \pi r^2 = \pi*0.1^2=0.0314m^2$

As the product of speed and cross-section area is constant, the speed in the smaller pipe would be

$AV = av$

$v = \frac{AV}{a} = \frac{0.196 * 1}{0.0314} = 6.25 m/s$

The mass flow rate would be:

$\dot{m} = \ro AV = 1000 * 0.196 * 1 = 196 kg/s$

4 0

3 years ago

Does weight increase decrease or stays constant as altitude increases

mojhsa [17]

Answer: It stays the same, it is constant no matter what.

Explanation: Just because it may go faster/slower due to altitude change, it does not affect the weight.

4 0

4 years ago

7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is

Gekata [30.6K]

Answer:

Approximately $1\; \rm kg$ . (Assumption: $g = 9.8\; \rm m \cdot s^{-2}$ .)

Explanation:

Let the mass of this ball be $x\; \rm kg$ .

Initial gravitational potential energy of this ball: $m \cdot g \cdot h \approx (39.2\, x) \; \rm J$ .

Just before the ball hits the ground, all $(39.2\, x)\; \rm J$ of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:

$\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}$ .

Therefore, right before hitting the ground, the velocity of the ball would be:

$\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}$ .

The momentum $p$ of an object of mass $m$ and velocity $v$ would be $p = m \cdot v$ . Rewrite this equation to find an expression for mass $m\!$ given velocity $v\!$ and momentum $p\!$ :

$\displaystyle m = \frac{p}{v}$ .

Right before collision, the momentum of this ball is $p = 8.85\; \rm kg \cdot m \cdot s^{-1}$ while its velocity is $v \approx 8.85\; \rm m \cdot s^{-1}$ . Therefore, the mass of this ball would be:

$\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}$ .

7 0

3 years ago

Two spheres are attracted to each other through the force of gravity. If you triple the distance between the two spheres what ha

garik1379 [7]

Answer:

its a

Explanation:

because spheres dont really have a magnetic force

8 0

3 years ago

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