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kap26 [50]
4 years ago
12

Which of the following statements are true? Check all that apply. A.Earth's geographic south pole is also a magnetic south pole.

B.Scientists have evidence that single isolated magnetic poles, called magnetic monopoles, exist. C.The north pole of a bar magnet will attract the south pole of another bar magnet. D.The south poles of two bar magnets will repel each other. E.The north poles of two bar magnets will attract each other. F.Earth's geographic north pole is actually a magnetic south pole.
Physics
1 answer:
ycow [4]4 years ago
4 0

Answer:

C.The north pole of a bar magnet will attract the south pole of another bar magnet.

D.The south poles of two bar magnets will repel each other.

F.Earth's geographic north pole is actually a magnetic south pole.

Explanation:

The magnetic field is a region of space that exerts a force on charged particles in motion or on magnets.

A magnet is an object that produces a magnetic field in the region around it - a magnet always consists of a north pole and of a south pole; it is not possible to create a magnetic monopole: if a magnet is cut in a half, we end up with two new magnets, each of them having its own north and south pole.

The lines showing the direction of the magnetic field always go from the north pole towards the south pole.

When a magnet is placed near another magnet, the two magnets can attract/repel each other. In particular:

- Same poles (north-north and south-south) repel each other

- Opposite poles (north-south) attract each other

Moreover, the Earth has also a magnetic field, and its axis acts as a huge magnet. The location of the magnetic North pole corresponds to the location of the geographic South pole, and vice-versa.

According to what we said so far, the correct statements are:

C.The north pole of a bar magnet will attract the south pole of another bar magnet.

D.The south poles of two bar magnets will repel each other.

F.Earth's geographic north pole is actually a magnetic south pole.

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The reactivity of metals increases as you move left in a period and as you move down in a group, so Marie needs to know the period and group of the element inside each box. Boxes that show locations in groups 1 or 2 or in period 8 contain the most reactive elements.

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3 years ago
An electron is accelerqated in the uniform field betwen two parallel charged oplates. The separation of the plates is 1.20 cm
marysya [2.9K]

Answer:

The speed of electron is 8.7\times10^{6}\ m/s

Explanation:

Given that,

Separation of the plate = 1.20 cm

Suppose the field is E=1.80\times10^{4}\ N/C.

If the electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.

What the speed does it leave the hole?

We need to calculate the acceleration

Using formula of electric force

F = qE

ma=qE

a=\dfrac{qE}{m}

We need to calculate the speed of electron

Using equation of motion

v^2=u^2+2as

v^2=2as

Put the value of acceleration in the formula

v^2=2\times\dfrac{qE}{m}\times s

Put the value into the formula

v^2=2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}

v=\sqrt{2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}}

v=8.7\times10^{6}\ m/s

Hence, The speed of electron is 8.7\times10^{6}\ m/s

7 0
3 years ago
Suppose you add two vectors A and B . What relative direction between them produces the resultant with the greatest magnitude? W
Akimi4 [234]

Answer:

Same direction to produce maximum magnitude and opposite direction to produce minimum magnitude

Explanation:

Let a be the angle between vectors A and B. Generally when we add A to B, we can split A into 2 sub vectors, 1 parallel to B and the other perpendicular to B.

Also let A and B be the magnitude of vector A and B, respectively.

We have the parallel component after addition be

Acos(a) + B

And the perpendicular component after addition be

Asin(a)

The magnitude of the resulting vector would be

\sqrt{(Acos(a) + B)^2 + (Asin(a))^2}

= \sqrt{A^2cos^2a + B^2 + 2ABcos(a) + A^2sin^2a}

= \sqrt{A^2(cos^2a + sin^2a) + B^2 + 2ABcos(a)}

= \sqrt{A^2 + B^2 + 2ABcos(a)}

As A and B are fixed, the equation above is maximum when cos(a) = 1, meaning a = 0 degree and vector A and B are in the same direction, and minimum with cos(a) = -1, meaning a = 180 degree and vector A and B are in opposite direction.

8 0
4 years ago
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